Then calculate wind pressure This really puzzles me, why isn't alignment enforced for t What alignment do you want it to have? Shorts can be aligned on 2 byte boundaries with no ill effects(assuming common x86 compilers all over here.. You can always get the number of elements in an array by doing sizeof(arrayofT)/sizeof(T), and array elements are guaranteed to be stored adjacently, such that the n'th element can be retreived by stepping N*sizeof(arrayelementtype) bytes from the start, and that's the main reason you'll see structs being padded at the end. ) So if you create an array of struct ThreeeShorts, that struct having a size of 6 is fine, as any elements in such an array will start on a 2 byte boundary.. If we didn't consider arrays, it wouldn't matter much if struct IntAndChar were 5 bytes long, the compiler would just allocate it starting on a 4 byte boundary when you create one one the stack, or use it as a compound member in another struct.. May 29, 2018 To calculate wind load using the generic formula, use F = A × P × Cd, where F is the force or wind load, A is the projected area of the object, P is the wind pressure, and Cd is the drag coefficient.. Your struct IntAndChar contains an int, ints wants 4 byte alignment, so if you create an array of struct IntAndChar the size have to be 8 for the next element to be aligned on a 4 byte boundary.. First find A, the area of the 2-dimensional face the wind is hitting, using A = length × height for a flat wall. Aplikasi Pengunduh Video Youtube Android Auto
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